Web11 I can overload the parenthesis operator using the following signature: char& operator () (const int r, const int c); The intended usage of this would be: // myObj is an object of type MyClass myObj (2,3) = 'X' char Y = myObj (2,3); Which works as I expect. However, using the parenthesis operator when dealing with a pointer becomes convoluted.WebFeb 26, 2024 · struct MyClassComparator { bool operator () (const MyClass & obj1, const MyClass & obj2) const { if (obj1.getName () == obj2.getName ()) return true; return false; } }; So I am comparing the names (strings) of the objects (nothing fancy). I use this to find a MyClass object in a set using .find function.
c++ - How overload operator < for sort method for objects
WebMar 17, 2016 · I know how overload sort method for vector when I have one parameter for sorting. It's like: bool operator< (Employee a, Employee b ) { if (a.name
c++ - What can I use instead of the arrow operator ... - Stack Overflow
WebAnother good example of when operator overloading makes code more clear is smart pointers in C++. You want the smart pointers to behave like regular pointers as much as possible, so it makes perfect sense to overload the unary * and -> operators. In essence, operator overloading is nothing more than just another way to name a function.WebWhen parsing an expression, an operator which is listed on some row of the table above with a precedence will be bound tighter (as if by parentheses) to its arguments than any operator that is listed on a row further below it with a lower precedence.Web11. I can overload the parenthesis operator using the following signature: char& operator () (const int r, const int c); The intended usage of this would be: // myObj is an object of …colour changing bath bombs